Apex Method of the Day – JSON.deserialize(jsonString, List.class)

Posted on November 8, 2012 by Stephen 
List<Foo> f = (List<Foo>) JSON.deserialize(jsonString, List<Foo>.class);

Force.com Apex Code Developer’s Guide – JSON Methods

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1 Response to Apex Method of the Day – JSON.deserialize(jsonString, List.class)

  1. Sam Nathan says:
    July 12, 2019 at 1:01 am

    Thank you, this saved me some research !

    Like

    Reply

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